w^2+5w-149=0

Solution for w^2+5w-149=0 equation:

w^2+5w-149=0

a = 1; b = 5; c = -149;
Δ = b2-4ac
Δ = 52-4·1·(-149)
Δ = 621
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{621}=\sqrt{9*69}=\sqrt{9}*\sqrt{69}=3\sqrt{69}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-3\sqrt{69}}{2*1}=\frac{-5-3\sqrt{69}}{2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+3\sqrt{69}}{2*1}=\frac{-5+3\sqrt{69}}{2}
$